document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99246>Question 99246</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please take the time to help me solve this problem: In a right triangle, the length of the hypotenuse is 5 and the length of one of the legs is 3, determine the tangents off all three angles. I would be really appreciate it if you did help me.\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72209 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72209\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, find the lengths of all the sides<BR>\n" );
document.write( "(hypotenuse)2 = (side1)2 + (side2)2<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2A2+=+3%2A2+%2B+x%2A2 ALIGN=MIDDLE  ALT=\"5%2A2+=+3%2A2+%2B+x%2A2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2A2+=+5%2A2+-+3%2A2 ALIGN=MIDDLE  ALT=\"x%2A2+=+5%2A2+-+3%2A2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2A2+=+25+-+9 ALIGN=MIDDLE  ALT=\"x%2A2+=+25+-+9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2A2+=+16 ALIGN=MIDDLE  ALT=\"x%2A2+=+16\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+4 ALIGN=MIDDLE  ALT=\"x+=+4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "It's what is known as a 3-4-5 triangle<BR>\n" );
document.write( "The tangent function in trig is (opposite side) / (adjacent side)<BR>\n" );
document.write( "For the angle opposite the length 3 side, call it A<BR>\n" );
document.write( "Tan A = 3/4<BR>\n" );
document.write( "For the angle opposite the length 4 side, call it B<BR>\n" );
document.write( "Tan B = 4/3<BR>\n" );
document.write( "The remaining angle, opposite the hypotenuse is 90 degrees, as<BR>\n" );
document.write( "with any right triangle. Call it C<BR>\n" );
document.write( "Tan C = Tan 90 <BR>\n" );
document.write( "Tan 90 = infinity. This is because the adjacent side is zero<BR>\n" );
document.write( "and the reciprocal of zero is infinity. You need to plot it on<BR>\n" );
document.write( "the unit circle to see this. </SPAN>\n" );
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