document.write( "Question 1107013: can some one please help me Solve the system using addition:\r
\n" ); document.write( "\n" ); document.write( "x/2 + y = 5/2\r
\n" ); document.write( "\n" ); document.write( "x/3 -y/3 = -1/3\r
\n" ); document.write( "\n" ); document.write( "I cannot seem to figure this out I am stumped on how to get opposite coefficients.
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Algebra.Com's Answer #722020 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
x/2 + y = 5/2\r
\n" ); document.write( "\n" ); document.write( "x/3 -y/3 = -1/3\r
\n" ); document.write( "\n" ); document.write( "I cannot seem to figure this out I am stumped on how to get opposite coefficients.
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\n" ); document.write( "IDK what \"opposite coefficients\" are.
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\n" ); document.write( "Multiply the 2nd eqn by 3, then add them
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