document.write( "Question 1106959: TWO DIFFERENT SOLUTIONS OF ALCOHOL WITH RESPECTIVE PROPORTIONS OF WATER TO ALCOHOL OF 3:1 AND 3:2 WERE COMBINED .WHAT IS THE CONCENTRATION OF ALCOHOLIN THE NEW SOLUTION SOLUTION IF THE ORIGINAL SOLUTIONS WERE MIXED IN EQUAL AMOUNT \n" ); document.write( "
Algebra.Com's Answer #721968 by stanbon(75887)\"\" \"About 
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TWO DIFFERENT SOLUTIONS OF ALCOHOL WITH RESPECTIVE PROPORTIONS OF WATER TO ALCOHOL OF 3:1 AND 3:2 WERE COMBINED .WHAT IS THE CONCENTRATION OF ALCOHOL IN THE NEW SOLUTION SOLUTION IF THE ORIGINAL SOLUTIONS WERE MIXED IN EQUAL AMOUNT
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\n" ); document.write( "3:1 means 1/4 alcohol or 25% alcohol
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\n" ); document.write( "3/2 means 2/5 alcohol or 40% alcohol
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\n" ); document.write( "Let \"a\" be the amt of each liquid.
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\n" ); document.write( "Alcohol Eq:: 0.25a + 0.40a = (x/100)(2a)
\n" ); document.write( "25a + 40a = x(2a)
\n" ); document.write( "65a = 2xa
\n" ); document.write( "2x = 65
\n" ); document.write( "x = 32.5% alcohol in the new solution
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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