document.write( "Question 1106955: Hi
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document.write( "Andrew Lionel and caroline shared a sum of money. Andrew's share was 0.25 of the total amount received by Lionel and caroline. Lionel s share was 1/3 of the sum of money. If andrew received 60 dollars less than Lionel, how much did Lionel receive.\r
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document.write( "thanks \n" );
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Algebra.Com's Answer #721965 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A = Andrew's amt \n" ); document.write( "L = Lionel's amt \n" ); document.write( "C = Caroline's amt \n" ); document.write( ": \n" ); document.write( "Andrew Lionel and caroline shared a sum of money. \n" ); document.write( "A+B+C is the sum money \n" ); document.write( ": \n" ); document.write( " Andrew's share was 0.25 of the total amount received by Lionel and Caroline. \n" ); document.write( "A = .25(L+C) \n" ); document.write( "Multiply both sides by 4 \n" ); document.write( "4A = L + C \n" ); document.write( "or \n" ); document.write( "C = 4A - L \n" ); document.write( ": \n" ); document.write( "Lionel's share was 1/3 of the sum of money. \n" ); document.write( "L = \n" ); document.write( "multiply both sides by 3 \n" ); document.write( "3L = (A+L+C) \n" ); document.write( "3L = A + L + C \n" ); document.write( "subtract L from both sides \n" ); document.write( "2L = A + C \n" ); document.write( "Replace C = (4A-L) \n" ); document.write( "2L = A + 4A - L \n" ); document.write( "2L = A + 4A - L \n" ); document.write( "2L + L = 5A \n" ); document.write( "3L = 5A \n" ); document.write( "If andrew received 60 dollars less than Lionel, \n" ); document.write( "A = L - 60 \n" ); document.write( "Replace A with (L-60) in the equation 3L = 5A \n" ); document.write( "3L = 5(L-60) \n" ); document.write( "3L = 5L - 300 \n" ); document.write( "3L - 5L = -300 \n" ); document.write( "-2L = -300 \n" ); document.write( "L = -300/-2 \n" ); document.write( "L = $150 is received by Lionel\r \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( " |