document.write( "Question 1106923: Mary is twice as old as Judy. Six years ago Mary was three times as old as Judy. Find the age of each perso now. \n" ); document.write( "

Algebra.Com's Answer #721961 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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m = Mary's present age
\n" ); document.write( "j = Judy's
\n" ); document.write( ":
\n" ); document.write( "Mary is twice as old as Judy.
\n" ); document.write( "m = 2j
\n" ); document.write( "Six years ago Mary was three times as old as Judy.
\n" ); document.write( "m-6 = 3(j-6)
\n" ); document.write( "m - 6 = 3j - 18
\n" ); document.write( "m = 3j - 18 + 6
\n" ); document.write( "m = 3j - 12
\n" ); document.write( " Find the age of each person now.
\n" ); document.write( "Replace m with 2j
\n" ); document.write( "2j = 3j - 12
\n" ); document.write( "2j - 3j = -12
\n" ); document.write( "-j = -12
\n" ); document.write( "j = 12 yrs is Judy's names
\n" ); document.write( "therefore
\n" ); document.write( "2(12) = 24 yrs is Mary's name
\n" ); document.write( ":
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\n" ); document.write( "Check this in the statement \"Six years ago Mary was three times as old as Judy.\"
\n" ); document.write( "24 - 6 = 3(12-6)
\n" ); document.write( "18 = 3(6)
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