document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1106611>Question 1106611</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't know if I'm in the right section or anything, but just need to know the steps and answer to this simple chance experiment:\r<BR>\n" );
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document.write( "I have a jar of 60 marbles. 58 are blue and 2 are red. If I draw out a marble 15 times without putting any back, what is the chance I draw both red marbles?\r<BR>\n" );
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document.write( "Thank you very much in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #721957 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=721957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Chance don't draw either is 58/60*57/59*56/58*...*44/46=0.5593<BR>\n" );
document.write( "That is the brute force method.<BR>\n" );
document.write( "for 0 is 58C15/60C15, or 0.5593\r<BR>\n" );
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document.write( "for 1 is 0.3813, 58C14*2C1/60C15\r<BR>\n" );
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document.write( "for both is 58C13*2C2 (which is 1)/60C15, or 0.0593 answer. </SPAN>\n" );
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