document.write( "Question 1105123: A container filled with 30 litres of wine had 5 litres of wine removed. To fill the container. 5 litres of water was added. The next day 12 litres of the mixture was removed, and replaced with an equal amount of water. What fraction of the final mixture was water? \n" ); document.write( "
Algebra.Com's Answer #721951 by JThomson(12)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "After 5 litres of wine is removed and 5 litres of water added, the ratio of \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "wine to water is 25 : 5;\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thus there is 5/6 wine and 1/6 water in the mixture now;\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When 12 litres of the mixture is removed;\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(5/6)×12 = 10 litres of wine is removed;\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also (1/6)×12 = 2 litres of water is removed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Ratio of wine to water remaining is (25-10):(5-2)= 15:3;\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "After 12 litres of water has been added to mixture, ratio of wine to water \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "becomes, 15:(3+12) = 15:15 = 1:1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Fraction of water in the mixture now is 1/2. \n" ); document.write( " \n" ); document.write( " |