document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1106622>Question 1106622</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1) Assume that daily TV viewing is normally distributed and has a mean of 8 hours per household with a standard deviation of 2 hours. Find the following probabilities:<BR>\n" );
document.write( "a- Probability that a randomly selected household views TV more than  10 hours a day, i.e. P( x > 10)<BR>\n" );
document.write( "b- Probability that a randomly selected household views TV more more than 11 hours a day, i.e. P(x > 11)<BR>\n" );
document.write( "c- Probability that a randomly selected household views TV less than 3 hours a day, i.e. P(x < 3)<BR>\n" );
document.write( "d- Probability that a randomly selected household views TV between 10 and 12 hours a day, i.e. P( 10 < x < 12)\r<BR>\n" );
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document.write( "2) A company produces light bulbs with an average product life of 1000 hours and a standard deviation of 100 hours. Assume a normal distribution and answer the following:<BR>\n" );
document.write( "a- What percentage of light bulbs produced are expected to last longer than 1000 hours, i.e. P(x > 1000)? Express your answer in decimals.<BR>\n" );
document.write( "b- What percentage of light bulbs produced are expected to last shorter than 800 hours, i.e. P(x < 800)? Express your answer in decimals.<BR>\n" );
document.write( "c- What percentage of light bulbs produced are expected to last between 700 and 800 hours, i.e. P(700 < x < 800)? Express your answer in decimals.<BR>\n" );
document.write( "d- What percentage of light bulbs produced are expected to last between 1200 and 1300 hours, i.e. P(1200 > x > 1300)? Express your answer in decimals.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #721948 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=721948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sd<BR>\n" );
document.write( "(10-8)/2 or a z>1 or prob. 0.1587<BR>\n" );
document.write( "(11-8)/2 or z>1.5 or prob. 0.0668<BR>\n" );
document.write( "(3-8)/2=-2.5 or probability 0.0062<BR>\n" );
document.write( "That is a z between 1 and 2 or 0.1359\r<BR>\n" );
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document.write( "Longer than 1000 hours is 50% or 0.5<BR>\n" );
document.write( "fewer than 800 hours is a z < 2 or prob or 0.0228<BR>\n" );
document.write( "between 700 and 800 is -3 < z <-2 or prob 0.0214; the next one is the same except the z values are between 2 and 3.\r<BR>\n" );
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