document.write( "Question 1106926: Obtain the equation of the curve y=ax^2+bx+c,using the following conditions
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document.write( "(i) d²y/dx²=2
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document.write( "(ii) The curve is at minimum when x=-1/2
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document.write( "(iii) The curve passes through the point (-2,- 4). \n" );
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Algebra.Com's Answer #721922 by Fombitz(32388) You can put this solution on YOUR website! So, the first derivative is, \n" ); document.write( " \n" ); document.write( "and the second is, \n" ); document.write( " \n" ); document.write( "So, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( "Converting to vertex form, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So the minimum occurs at, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Finally using the point, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |