document.write( "Question 1106907: if solution a contains 60% calcuim and solution b contains 30% calcium.how much of each solution should be mixed in order to create 100 cups of a solution that contains 36% calcuim \n" ); document.write( "
Algebra.Com's Answer #721897 by josgarithmetic(39620)\"\" \"About 
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60% calcium solution? In what? As melted in something? Not a salt in water; right?\r
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\n" ); document.write( "if \"cross%28solution%29\" DRY MIXTURE a contains 60% calcuim and \"cross%28solution%29\" DRY MIXTURE b contains 30% calcium.how much of each \"cross%28solution%29\" should be mixed in order to create 100 cups of a \"cross%28solution%29\" that contains 36% calcuim
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\n" ); document.write( "\n" ); document.write( "That now begins to make some sense. The 100 \"cups\" of mixture is being measured in some container and would be marked in volume measurements. Still faulty unless the concentration is as v/v.\r
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\n" ); document.write( "\n" ); document.write( "x of the 60%
\n" ); document.write( "100-x of the 30%\r
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\n" ); document.write( "\n" ); document.write( "\"60x%2B30%28100-x%29=36%2A100\"\r
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\n" ); document.write( "\n" ); document.write( "\"6x%2B3%28100-x%29=360\"
\n" ); document.write( "\"6x%2B300-3x=360\"
\n" ); document.write( "\"3x=60\"
\n" ); document.write( "\"x=20\"
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\n" ); document.write( "\"100-x=80\"
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\n" ); document.write( "20 cups of the 60% calcium material
\n" ); document.write( "and
\n" ); document.write( "80 cups of the 30% calcium material
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