document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1106872>Question 1106872</A>: <I><SPAN STYLE=\"word-break: break-all;\">  metalworker has a metal alloy that is 3030&#8203;% copper and another alloy that is 6565&#8203;% copper. How many kilograms of each alloy should the metalworker combine to create 120120 kg of a 5151&#8203;% copper&#8203; alloy?\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #721866 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=721866\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x, mass of the 30% copper alloy<BR>\n" );
document.write( "120-x, mass of the 65% alloy\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=30x%2B65%28120-x%29=51%2A120 ALIGN=MIDDLE  ALT=\"30x%2B65%28120-x%29=51%2A120\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( ".\r<BR>\n" );
document.write( "\n" );
document.write( ".\r<BR>\n" );
document.write( "\n" );
document.write( ". </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );