document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1106876>Question 1106876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is twice its width. the perimeter is 90 cm what is the area of the rectangle<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #721862 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=721862\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is twice its width. the perimeter is 90 cm what is the area of the rectangle<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "L = 2*W<BR>\n" );
document.write( "2(L+W) = 90<BR>\n" );
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document.write( "L = 2*W<BR>\n" );
document.write( "L + W = 45<BR>\n" );
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document.write( "Substitute for \"L\" and solve for \"W\"::<BR>\n" );
document.write( "2W + W = 45<BR>\n" );
document.write( "3W = 45<BR>\n" );
document.write( "Width = 15 cm<BR>\n" );
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document.write( "L = 2*W = 30 cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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