document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1106849>Question 1106849</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x. Round your answer to 2 decimal places. \r<BR>\n" );
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document.write( "A right triangle is shown where the angle between the hypotenuse, of length x units, and a leg, of length eighteen units, is fifty degrees. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #721841 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=721841\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So we are solving for the length of the hypotenuse:<BR>\n" );
document.write( "Short leg: 18<BR>\n" );
document.write( "hypotenuse: x<BR>\n" );
document.write( "angle (see picture below): 50 degrees<BR>\n" );
document.write( "Since the acute angles in any right triangle are complementary (they add up to 90°):<BR>\n" );
document.write( "other acute angle: 90-50 = 40<BR>\n" );
document.write( "I'm going to use this second angle to get your answer:<BR>\n" );
document.write( "csc(40) = hypotenuse/18<BR>\n" );
document.write( "csc(40) * 18 = hypotenuse<BR>\n" );
document.write( "1.556 * 18 = hypotenuse<BR>\n" );
document.write( "hypotenuse = 28<BR>\n" );
document.write( " <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/display-illustration.mpl?tutor=addingup&illustration_name=triangle.JPG\"><BR>\n" );
document.write( " </SPAN>\n" );
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