document.write( "Question 99188: Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina? \n" ); document.write( "

Algebra.Com's Answer #72184 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?
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\n" ); document.write( "When J catches up with M, they will have traveled the same distance, make a distance equation from that fact:
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\n" ); document.write( "Let t = time required for J to catch up with M
\n" ); document.write( "Then
\n" ); document.write( "(t+2) = time that M will be on the road when this happens
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\n" ); document.write( "Dist = speed * time
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\n" ); document.write( "J's Dist = M's dist
\n" ); document.write( "48t = 24(t+2)
\n" ); document.write( "48t = 24t + 48
\n" ); document.write( "48t - 24t = 48
\n" ); document.write( "t = 48/24
\n" ); document.write( "t = 2 hrs
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\n" ); document.write( "J left at 11 so at 1 PM J will catch up with M
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\n" ); document.write( "Check solution by finding if the distances are equal
\n" ); document.write( "48(2) = 24(2+2) \n" ); document.write( "

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