document.write( "Question 1106763: Carl and Antonio are friends who live 20 miles apart. They are making plans to meet up. Carl will walk from his house towards Antonio's. Carl can walk at a speed of 4 mph. Antonio will jog from his house to Carl's. Antonio can jog at a speed of 6 mph. Their wives will pick them up. If they both leave at the same time, how long will it take them to meet up? \n" ); document.write( "
Algebra.Com's Answer #721745 by stanbon(75887)\"\" \"About 
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Carl and Antonio are friends who live 20 miles apart. They are making plans to meet up. Carl will walk from his house towards Antonio's. Carl can walk at a speed of 4 mph. Antonio will jog from his house to Carl's. Antonio can jog at a speed of 6 mph. Their wives will pick them up. If they both leave at the same time, how long will it take them to meet up?
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\n" ); document.write( "Carl Data:: distance = 4t where t is the time he walks
\n" ); document.write( "Antonio DATA: distance = 6t where ti is the time he jogs
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\n" ); document.write( "Equation:
\n" ); document.write( "4t + 6t = 20 miles
\n" ); document.write( "10t = 20 miles
\n" ); document.write( "time = 2 hrs
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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