document.write( "Question 1106756: A rectangular parcel of land is 70 ft longer than it is wide. Each diagonal between opposite corners is 130 ft. What are the dimensions of the parcel?
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document.write( "smaller side ft
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document.write( "larger side ft
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Algebra.Com's Answer #721738 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! width=x \n" ); document.write( "length=x+70 \n" ); document.write( "diagonal is 130 \n" ); document.write( "This is a right triangle. \n" ); document.write( "Square the sides: x^2+(x+70)^2=130^2, the square of the diagonal-hypotenuse \n" ); document.write( "x^2+x^2+140x+4900=16900 \n" ); document.write( "2x^2+140x-12000=0 \n" ); document.write( "x^2+70x-6000=0 \n" ); document.write( "(x+120)(x-50)=0 \n" ); document.write( "positive root only is x=50 feet width \n" ); document.write( "x+70=120 feet length. \n" ); document.write( "diagonal is 130 feet \n" ); document.write( "It is a 5-12-13 right triangle. \n" ); document.write( " |