document.write( "Question 1106730: if two dice are thrown , what are the various total number of dots that may turn up? what are the probabilities of each of them?
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Algebra.Com's Answer #721708 by math_helper(2461)\"\" \"About 
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Since there are only 11 possible outcomes (2…12 inclusive), we can enumerate them with the number of ways they can each be formed:\r
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document.write( "Outcome    # ways          
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document.write( "2                     1
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document.write( "3                     2   ((1,2) or  (2,1) on the roll of two dice) 
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document.write( "4                     3   ((2,2), (1,3), (3,1))
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document.write( "5                     4   ((1,4),(2,3),(3,2), and (4,1))
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document.write( "6                     5   
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document.write( "7                     6
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document.write( "8                     5
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document.write( "9                     4
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document.write( "10                   3
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document.write( "11                    2
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document.write( "12                    1
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document.write( "                     ———
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document.write( "                      36 possible outcomes\r
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document.write( "The probabilities are then just the (# of ways for a given outcome) / 36.\r
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document.write( "For instance:
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document.write( "  rolling a 2 has probability  1/36 
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document.write( "  7 is the most likely outcome, with probability  6/36 = 1/6\r
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document.write( "You can compute the rest similarly.\r
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