document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1106636>Question 1106636</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is five times its width. <BR>\n" );
document.write( "If the perimeter of the rectangle is <BR>\n" );
document.write( "84 ft find its area.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #721637 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=721637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1)  L = 5W<BR>\n" );
document.write( "(2) 2L + 2W = 84ft\r<BR>\n" );
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document.write( "(2')  2(5W) + 2W = 84ft\r<BR>\n" );
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document.write( "Solve (2') for W, then you can use (1) to get L,  then area = L*W  in sq ft.   I get 245 sq ft.<BR>\n" );
document.write( "Message me if you get stuck/need help.\r<BR>\n" );
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