document.write( "Question 1106629: the sum of ages of two sisters is 38years.four years ago the age of the elder sister was the square of the younger sister 's age.Find their ages? \n" ); document.write( "
Algebra.Com's Answer #721629 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"system%28x%2By=38%2Cy-4=%28x-4%29%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"38-x-4=x%5E2-8x%2B16\"
\n" ); document.write( "\"-x%2B34=x%5E2-8x%2B16\"
\n" ); document.write( "\"x%5E2-7x%2B16-34=0\"
\n" ); document.write( "\"x%5E2-7x-18=0\"
\n" ); document.write( "\"%28x-9%29%28x%2B2%29=0\"
\n" ); document.write( "\"highlight%28x=9%29\"--------younger sister\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28y=29%29\"-------older sister\r
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\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "recheck
\n" ); document.write( "\"29-4=%289-4%29%5E2\"
\n" ); document.write( "\"25=5%5E2\"
\n" ); document.write( "\"ok\"
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