document.write( "Question 1106587: Draw the graph of the relation defined by:\r
\n" ); document.write( "\n" ); document.write( "y^2 = 4x\r
\n" ); document.write( "\n" ); document.write( "Steps: first choose the vertex of the equation
\n" ); document.write( "Select one point above the axis of symmetry and one point below the axis of symmetry
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Algebra.Com's Answer #721602 by josgarithmetic(39617)\"\" \"About 
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Like parabola but symmetry axis is horizontal, the x-axis.\r
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\n" ); document.write( "\n" ); document.write( "y=-2sqrt(x) and y=2sqrt(x).\r
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\n" ); document.write( "\n" ); document.write( "Vertex is the origin. The graph has no points to the left of the origin.\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-3%2C10%2C-5%2C8%2C-2sqrt%28x%29%2C2sqrt%28x%29%29\"
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