document.write( "Question 99195: Write an equation in slope-intercept form of the line that is perpendicular to the graph of y=3x+17 and passes through (-7,4) \n" ); document.write( "

Algebra.Com's Answer #72160 by checkley71(8403) $\"\"$ $\"About$

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Y=mX+b WHERE X&Y ARE ONE SET OF COORDINATES, m=SLOPE & b=THE Y INTERCEPT.
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\n" ); document.write( "Y=3X+17 (RED LINE)
\n" ); document.write( "THIS LINE HAS A SLOPE=3 THUS A LINE PERPENDICULAR HAS A SLOPE OF -1/3.
\n" ); document.write( "NOW REPLACE THE X & Y TERMS WITH (-7,4) & SOLVE FOR THE Y INTERCEPT
\n" ); document.write( "4=-1/3*-7+b
\n" ); document.write( "4=7/3+b
\n" ); document.write( "b=4-7/3
\n" ); document.write( "b=(12-7)/3
\n" ); document.write( "b=5/3 FOR THE Y INTERCEPT. THUS THE LINE EQUATION IS:
\n" ); document.write( "Y=-X/3+5/3 (GREEN LINE)
\n" ); document.write( " $\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+3x+%2B17%2C+y+=+-x%2F3+%2B5%2F3%29+\"$ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions y = 3x +17 and y = -x/3 +5/3). \n" ); document.write( "

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