document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1106559>Question 1106559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A regular pentagon ABCDE and a square ABFG are formed on opposite sides of AB. Find angle BCF </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #721587 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=721587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "(1) Angle ABF is 90 degrees.<BR>\n" );
document.write( "(2) Angle ABC is 108 degrees.<BR>\n" );
document.write( "(3) You can find the measure of angle CBF knowing that angles ABF, ABC, and CBF sum to 360 degrees.<BR>\n" );
document.write( "(4) The square and pentagon have the same side length, so triangle CBF is isosceles.  Knowing the measure of angle CBF lets you determine the measure of angle BCF. </SPAN>\n" );
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