document.write( "Question 1106491: In the arithmetic series, if S_n = 5n^2+4n, find the first three terms.\r
\n" ); document.write( "\n" ); document.write( "So the first term is 9, and I tried using the formula S_n= (a1+an)/2 * n\r
\n" ); document.write( "\n" ); document.write( "I got confused... does an = 5n^2+4n
\n" ); document.write( "

Algebra.Com's Answer #721490 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The sum of n terms of an arithmetic series is

\n" ); document.write( "(number of terms) times (average of first and last terms)

\n" ); document.write( "If the first term is a and the common difference is d, then the sum of the first and last terms is
\n" ); document.write( "\"a+%2B+a%2B%28n-1%29d+=+2a%2B%28n-1%29d\"
\n" ); document.write( "and the sum of the first n terms is then
\n" ); document.write( "\"n%28%282a%2B%28n-1%29d%29%2F2%29\"

\n" ); document.write( "We are told that the sum of the first n terms of the sequence is 5n^2+4n. So

\n" ); document.write( "\"n%28%282a%2B%28n-1%29d%29%2F2%29+=+5n%5E2%2B4n\"
\n" ); document.write( "\"n%282a%2Bdn-d%29+=+10n%5E2%2B8n\"
\n" ); document.write( "\"dn+%2B+%282a-d%29+=+10n%2B8\"

\n" ); document.write( "This tells us
\n" ); document.write( "\"dn+=+10n\" which means d is 10, and
\n" ); document.write( "\"2a-d+=+8\"
\n" ); document.write( "\"2a-10+=+8\"
\n" ); document.write( "\"2a+=+18\"
\n" ); document.write( "\"a+=+9\"

\n" ); document.write( "So the arithmetic series has first term 9 and common difference 10.

\n" ); document.write( "Then the first three terms are 9, 19, and 29.
\n" ); document.write( "
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