document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1106481>Question 1106481</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two consecutive odd integers such that their product is 119 more than 7 times their sum. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #721457 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=721457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x and x+2 are the integers<BR>\n" );
document.write( "x(x+2)=7(x+x+2)+119<BR>\n" );
document.write( "x^2+2x=7(2x+2)+119=14x+133<BR>\n" );
document.write( "x^2-12x-133=0<BR>\n" );
document.write( "(x-19)(x+7)=0<BR>\n" );
document.write( "x=19, x+2=21<BR>\n" );
document.write( "(19 and 21) sum is 40 product is 399, which is 119 more than 280.  ANSWER<BR>\n" );
document.write( "also<BR>\n" );
document.write( "x=-7, x+2=-5<BR>\n" );
document.write( "(-7 and -5), sum is -12 and product is 35. That is 119 more than -84, 7 times their sum.  ANSWER<BR>\n" );
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