document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1106459>Question 1106459</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man deposited $300000 in his savings account at 8.5 perannum compound<BR>\n" );
document.write( "interest.He then add $50000 to his saving at the end of each year.<BR>\n" );
document.write( "Calculate his total savings for 3 years </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #721450 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=721450\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Easiest way to do this is by year<BR>\n" );
document.write( "300000*0.085=25500<BR>\n" );
document.write( "325500 after 1 year plus 50000 is 375500<BR>\n" );
document.write( "after 2 years 31917.50 is added +50000 so the new total is 457417.50<BR>\n" );
document.write( "after 3 years 38,880.48 is added + 50000, so final total is $546,297.99 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );