document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1106451>Question 1106451</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Onyango and kamau were employed on the same day and their salaries were as follows. Onyango:sh.11,000 per month and an increment of sh.300 at the end of every year. Kamau: sh 10,000 per month and an increment of sh 500 at the end of every year. After how many years will they earn equal salaries ?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #721432 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=721432\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> O is making 1000 per month more <BR>\n" );
document.write( "At the end of each year, that difference lessens by 200 (500-300)<BR>\n" );
document.write( "after 6 years, the salaries will be equal. It's 6 because there is no change the first year.<BR>\n" );
document.write( "O. will make 11000+1500 (300*5 years)=12500 per month<BR>\n" );
document.write( "K. will make 10000+2500 (500*5 years)=12500 per month </SPAN>\n" );
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