document.write( "Question 1106425: Can I please get help in solving this question. Thanks :)
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Algebra.Com's Answer #721405 by ikleyn(52788) $\"\"$ $\"About$

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\n" ); document.write( "Can I please get help in solving this $\"highlight%28cross%28question%29%29\"$ equation. Thanks :)
\n" ); document.write( "e^2x - 5e^x + 6 = 0
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\n" ); document.write( "\n" ); document.write( " It is 129-th time as we, the tutors, ask you DO NOT USE words \"solve question\". There is no such term in English.\r
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\n" ); document.write( "\n" ); document.write( " Simply say \"solve equation\". T h a n k s.\r
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document.write( "Standard way is introducing new variable y = . \r\n" );
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document.write( "Then the equation takes the form\r\n" );
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document.write( "y^2 - 5x + 6 = 0.\r\n" );
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document.write( "Factor left side:\r\n" );
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document.write( "(y-2)*(y-3) = 0.\r\n" );
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document.write( "There are 2 solutions:  y = 2  and  y = 3.\r\n" );
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document.write( "1)  y = 2 ====>   = 2  ====>  x = ln(2).\r\n" );
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document.write( "2)  y = 3  ====>   = 3  ====>  x = ln(3).\r\n" );
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document.write( "Answer.  There are two solutions:  x = ln(2)   and   x = ln(3).\r\n" );
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document.write( "Check.   1)  x = ln(2):   =  =  = 4 - 10 + 6 = 0.  ! Correct !\r\n" );
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document.write( "         2)  x = ln(3):   =  =  = 9 - 15 + 6 = 0.  ! Correct !\r\n" );
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