document.write( "Question 1106396: Assume that​ women's heights are normally distributed with a mean given by mu equals 64.3 in μ=64.3 in​, and a standard deviation given by sigma equals 3.1 in σ=3.1 in.
\n" ); document.write( "​(a) If 1 woman is randomly​ selected, find the probability that her height is less than 65 in.
\n" ); document.write( "​(b) If 50 women are randomly​ selected, find the probability that they have a mean height less than 6565 in.
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Algebra.Com's Answer #721357 by Boreal(15235)\"\" \"About 
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z=(x-mean)/sd
\n" ); document.write( "z< (65-64.3)/3.1=z < +0.23
\n" ); document.write( "that probability is 0.5893\r
\n" ); document.write( "\n" ); document.write( "The second one is divided by the standard error, which is 3.1/sqrt(50)
\n" ); document.write( "That quotient is 0.438
\n" ); document.write( "z < 0.7/0.4380 <1.60
\n" ); document.write( "That probability is 0.9450; much less likely to find an average >65.
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