document.write( "Question 99123: This one really has me stumped. \r
\n" ); document.write( "\n" ); document.write( "Find the exact solution(s)of the system: x^2/4-y^2=1 and x=y^2+1\r
\n" ); document.write( "\n" ); document.write( "a. (4,√3),(4,-√3),(-4,√3),(-4,-√3)
\n" ); document.write( "b. (4,√3),(-4,√3)
\n" ); document.write( "c. (2,1),(2,-1),(4,√3),(4,-√3)
\n" ); document.write( "d. (4,√3),(4,-√3)\r
\n" ); document.write( "\n" ); document.write( "Thank you.
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Algebra.Com's Answer #72135 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x=y%5E2%2B1\" Start with the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"x-1=y%5E2\" Subtract 1 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F4-y%5E2=1+\" Now move onto the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F4-%28x-1%29=1+\" Replace \"y%5E2\" with \"x-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F4=1%2B%28x-1%29+\" Add \"x-1\" to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F4=x+\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=4x+\" Multiply both sides by 4\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-4x=0+\" Subtract 4x from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-4%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "\"x=0\" or \"x-4=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=0\" or \"x=4\" Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "Now let's use these two x-values to find the y-values\r
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\n" ); document.write( "\n" ); document.write( "Let's find y when x=0\r
\n" ); document.write( "\n" ); document.write( "\"x=y%5E2%2B1\" Start with the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"0=y%5E2%2B1\" Plug in x=0\r
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\n" ); document.write( "\n" ); document.write( "\"-1=y%5E2\" Subtract 1 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28-1%29=y\" Take the square root of both sides. Since you cannot take the square root of a negative number, x=0 is not in the solution\r
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\n" ); document.write( "\n" ); document.write( "Let's find y when x=4\r
\n" ); document.write( "\n" ); document.write( "\"x=y%5E2%2B1\" Start with the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"4=y%5E2%2B1\" Plug in x=4\r
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\n" ); document.write( "\n" ); document.write( "\"3=y%5E2\" Subtract 1 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"0%2B-sqrt%283%29=y\" Take the square root of both sides. So when x=4, \"y=0%2B-sqrt%283%29\" which means \"y=sqrt%283%29\" or \"y=-sqrt%283%29\" \r
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\n" ); document.write( "\n" ); document.write( "So our solution is \r
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\n" ); document.write( "\n" ); document.write( "(4,\"sqrt%283%29\"), (4,\"-sqrt%283%29\")\r
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\n" ); document.write( "\n" ); document.write( "which means the answer is D
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