document.write( "Question 1106383: question 1 find the value(s) of x for which
\n" ); document.write( "((x^3-7x^2+6x)/(x^5+4x^4-3))=0
\n" ); document.write( "question 2 determine the limiting value of (3n^2+1)/(4(n^2-2)) as n=∞ \n" ); document.write( "
Algebra.Com's Answer #721348 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Look for values that make the numerator equal to zero.
\n" ); document.write( "\"x%5E3-7x%5E2%2B6x=x%28x%5E2-7x%2B6%29\"
\n" ); document.write( "\"x%5E3-7x%5E2%2B6x=x%28x-1%29%28x-6%29%29\"
\n" ); document.write( "Potential zeros: x=0, x=1, x=6.
\n" ); document.write( "Verify that the denominator does not equal zero for any of these potential zeros.
\n" ); document.write( "If it doesn't, then it's a real zero.
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "
\n" ); document.write( "\"lim%28n-%3Einfinity%2C%28%283n%5E2%2B1%29%2F%284n%5E2-8%29%29%29=%283%2B0%29%2F%284-0%29\"
\n" ); document.write( "\"lim%28n-%3Einfinity%2C%28%283n%5E2%2B1%29%2F%284n%5E2-8%29%29%29=3%2F4\"\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );