document.write( "Question 1106349: 1+2logx\r
\n" ); document.write( "\n" ); document.write( "Express as the log of a single quantity.
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Algebra.Com's Answer #721307 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "No base is specified, so it is assumed the base is 10. Then

\n" ); document.write( "1 = log_10(10)
\n" ); document.write( "2log_10(x) = log_10(x^2)

\n" ); document.write( "Then
\n" ); document.write( "1+2logx
\n" ); document.write( " = 1+2log_10(x)
\n" ); document.write( " = log_10(10)+log_10(x^2)
\n" ); document.write( " = log_10[(10)*(x^2)]
\n" ); document.write( " = log_10(10x^2)
\n" ); document.write( " = log(10x^2)

\n" ); document.write( "Answer: 1+2logx = log(10x^2)
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