document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99106>Question 99106</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?<BR>\n" );
document.write( "At what time will John catch up with Martina?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72130 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72130\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> DISTANCE=RATE*TIME<BR>\n" );
document.write( "SEEING AS THESE DISTANCES ARE THE SAME WE SET UP THE EQUATION:<BR>\n" );
document.write( "24T=48(T-2)<BR>\n" );
document.write( "24T=48T-96<BR>\n" );
document.write( "-24T=-96<BR>\n" );
document.write( "T=96/24<BR>\n" );
document.write( "T=4 HOURS AFTER NOON THEY WILL MEET.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "24*4=48(4-2)<BR>\n" );
document.write( "96=48*2<BR>\n" );
document.write( "96=96<BR>\n" );
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