document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99119>Question 99119</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \"Suppose the temperature outside is dropping at a constant rate. At noon, the temperature is 70 degrees f and it drops to 58 degrees at 5:00 p.m. How much did the temperature change each hour? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72128 by </B><A HREF=/tutors/aboutme.mpl?userid=rcmcc><B>rcmcc(152)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rcmcc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rcmcc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72128\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve this problem you need 2 pieces of data.<BR>\n" );
document.write( "1. The amount of time that passes<BR>\n" );
document.write( "2. The temperature drop over that amount of time\r<BR>\n" );
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document.write( "Because you measure the time from noon (12) to (5) there has been a 5 hour time difference.\r<BR>\n" );
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document.write( "to find the temperature change subtract 58 from 70 and you get 12 degrees.\r<BR>\n" );
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document.write( "now divide the temperature by the time\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%2F5 ALIGN=MIDDLE  ALT=\"12%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" > is your answer. in decimal form 2.4 degrees per hour. </SPAN>\n" );
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