document.write( "Question 99119: \"Suppose the temperature outside is dropping at a constant rate. At noon, the temperature is 70 degrees f and it drops to 58 degrees at 5:00 p.m. How much did the temperature change each hour? \n" ); document.write( "
Algebra.Com's Answer #72127 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! (70-58)/5=12/5=2.4 DEGREE DROP PER HOUR. \n" ); document.write( " |