document.write( "Question 99093: i don't understand this at all solve each of the folowing quadratic equations by completing the square. \r
\n" ); document.write( "\n" ); document.write( "x^2 - 6x - 3 = 0
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Algebra.Com's Answer #72125 by Msgenes(10)\"\" \"About 
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x^2 - 6x -3 =0
\n" ); document.write( "we have to take 3 to the other side by adding 3 to both sides
\n" ); document.write( "x^2 - 6x -3 + 3= 0 +3
\n" ); document.write( "x^2 - 6x = 3
\n" ); document.write( "Now we have to complete the square by dividing 2 into 6 and then squaring it.
\n" ); document.write( "(6/2)^2 = (3)^2 = 9
\n" ); document.write( "Now we add 9 to both sides\r
\n" ); document.write( "\n" ); document.write( "x^2 - 6x + 9 = 3 + 9\r
\n" ); document.write( "\n" ); document.write( "(x-3)^2 = 12\r
\n" ); document.write( "\n" ); document.write( "Now we take the square root on both sides of the equation.\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28%28x-3%29%5E2%29=+sqrt%2812%29\"\r
\n" ); document.write( "\n" ); document.write( "x - 3 = 2\"sqrt%283%29\"
\n" ); document.write( "x - 3 + 3 = 3 + 2\"sqrt%283%29\"
\n" ); document.write( "x = 3 + 2\"sqrt%283%29\" or x = 3 - 2\"sqrt%283%29\"\r
\n" ); document.write( "\n" ); document.write( "Normally you would use the sqaure root sign and the plus or minus sign.
\n" ); document.write( "Hope this helps you...Good Luck...:)
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