document.write( "Question 1106289: The average of 10 numbers is 24. The average of first four numbers is 16*3/4 of the next three number is 22*1/3. If the eighth number be less than the ninth and tenth numbers by 11 and 8 respectively, then the tenth number is : \n" ); document.write( "
Algebra.Com's Answer #721249 by ankor@dixie-net.com(22740)\"\" \"About 
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The average of 10 numbers is 24.
\n" ); document.write( "Sum of 10 no. = 240
\n" ); document.write( ":
\n" ); document.write( " The average of first four numbers is 16*3/4
\n" ); document.write( "Sum of 1st four no.: 4*16.75 = 67
\n" ); document.write( ":
\n" ); document.write( " of the next three number is 22*1/3
\n" ); document.write( "sum of next three no.: 3 * 22.33 = 67
\n" ); document.write( ":
\n" ); document.write( "let x, y, z = the 8th, 9th & 10th numbers
\n" ); document.write( "Then we can write an equation
\n" ); document.write( "67 + 67 + x + y + z = 240
\n" ); document.write( "x + y + x = 240 - 134
\n" ); document.write( "x + y + z = 106
\n" ); document.write( ":
\n" ); document.write( " If the eighth number be less than the ninth and tenth numbers by 11 and 8 respectively,
\n" ); document.write( "x = y - 11
\n" ); document.write( "x = z - 8
\n" ); document.write( "x = x therefore
\n" ); document.write( "y - 11 = z - 8
\n" ); document.write( "y = z - 8 + 11
\n" ); document.write( "y = z + 3
\n" ); document.write( ":
\n" ); document.write( "then the tenth number is :
\n" ); document.write( "in the equation x + y + z = 106, replace x and y
\n" ); document.write( "(z-8) + (z+3) + z = 106
\n" ); document.write( "3z - 5 = 106
\n" ); document.write( "3z = 111
\n" ); document.write( "z = 111/3
\n" ); document.write( "z = 37 is the 10th number
\n" ); document.write( ":
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