document.write( "Question 1106241: An open box is formed by cutting a 5 inch square measured from each corner and folding up the sides. If the volume of the carton is then 40 in3, what was the length of a side of the original square of cardboard? \n" ); document.write( "

Algebra.Com's Answer #721212 by ikleyn(52786) $\"\"$ $\"About$

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\n" ); document.write( "An open box is formed by cutting a 5 inch square measured from each corner and folding up the sides.
\n" ); document.write( "If the volume of the carton is then 40 in3, what was the length of a side of the original square of cardboard?
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document.write( "Let x be \"the length of a side of the original square of cardboard\", which is under the question.\r\n" );
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document.write( "Then the dimensions of the bottom of the box are  x-2*5 = x - 10 inches.\r\n" );
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document.write( "Hence, the volume of the box is  5*(x-10)^2 cubic inches, and you have an equation\r\n" );
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document.write( "5*(x-10)^2 = 40.\r\n" );
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document.write( "It implies\r\n" );
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document.write( "(x-10)^2 =   ====>  (x-10)^2 = 8  ====>  x-10 = +/-  = +/-   ====>   = 10 +- .\r\n" );
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document.write( "But the value  (x-10) must be positive; it means that only   x=   is the solution.\r\n" );
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document.write( "Answer.  The original cardboard  was the square of the side length    inches.\r\n" );
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\n" ); document.write( "The solution by @josgarithmetic is W R O N G and I R R E L E V A N T.\r
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\n" ); document.write( "\n" ); document.write( "Simply ignore it . . . for your safety . . . \r
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