document.write( "Question 1106225: In three more years Michael’s grandmother will be six times as old as Michael was last year when Michael’s present age is added to his grandfather’s present age the total is 68 how old is each one now \n" ); document.write( "
Algebra.Com's Answer #721183 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! In three more years Michael’s grandmother will be six times as old as Michael was last year \n" ); document.write( "g + 3 = 6(m - 1) \n" ); document.write( "g + 3 = 6m - 6 \n" ); document.write( "g = 6m - 6 - 3 \n" ); document.write( "g = 6m - 9 \n" ); document.write( ": \n" ); document.write( " when Michael’s present age is added to his grandmother’s present age the total is 68 \n" ); document.write( "m + g = 68 \n" ); document.write( "replace g with (6m-9) \n" ); document.write( "m + 6m - 9 = 68 \n" ); document.write( "7m = 68 + 9 \n" ); document.write( "7m = 77 \n" ); document.write( "m = 11 yrs is M's age \n" ); document.write( "then \n" ); document.write( "g = 6(11) - 9 \n" ); document.write( "g = 66 - 9 \n" ); document.write( "g = 57 yrs is G's age \n" ); document.write( ": \n" ); document.write( "You should confirm this in both statements \n" ); document.write( " \n" ); document.write( " |