document.write( "Question 1106213: Jamie just paid off a loan he took out six months ago at 12% simple annual interest. He paid $3,816.00, which was the sum of the principal and the simple interest accrued over the length of the loan. What was the amount of principal he borrowed? \n" ); document.write( "
Algebra.Com's Answer #721180 by Boreal(15235) You can put this solution on YOUR website! principal of loan is Po \n" ); document.write( "P=Po*0.12*0.5, I=PRT \n" ); document.write( "Po+Interest=3816 \n" ); document.write( "Po+0.06Po=3816 \n" ); document.write( "1.06Po=3816 \n" ); document.write( "Po=$3600.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |