document.write( "Question 1106213: Jamie just paid off a loan he took out six months ago at 12% simple annual interest. He paid $3,816.00, which was the sum of the principal and the simple interest accrued over the length of the loan.  What was the amount of principal he borrowed? \n" ); document.write( "
Algebra.Com's Answer #721180 by Boreal(15235)\"\" \"About 
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principal of loan is Po
\n" ); document.write( "P=Po*0.12*0.5, I=PRT
\n" ); document.write( "Po+Interest=3816
\n" ); document.write( "Po+0.06Po=3816
\n" ); document.write( "1.06Po=3816
\n" ); document.write( "Po=$3600.\r
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