document.write( "Question 1106209: If x is not equal to -3, the slope of the line through (5,15) and (x+8, x2-2x) is \n" ); document.write( "
Algebra.Com's Answer #721178 by ankor@dixie-net.com(22740)\"\" \"About 
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If x is not equal to -3, the slope of the line through (5,15) and (x+8), (x^2-2x) is
\n" ); document.write( "use the slope formula: m = \"%28%28y2-y1%29%29%2F%28%28x2-x1%29%29\", where:
\n" ); document.write( "x1 = 5, y1 = 15
\n" ); document.write( "x2 = (x+8), y2 = (x^2-2x)
\n" ); document.write( "m = \"%28%28x%5E2-2x%29-15%29%2F%28%28x%2B8%29-5%29%29\"
\n" ); document.write( ":
\n" ); document.write( "m = \"%28%28x%5E2-2x-15%29%29%2F%28%28x%2B8-5%29%29\"
\n" ); document.write( "Factor the numerator
\n" ); document.write( "m = \"%28%28x-5%29%28x%2B3%29%29%2F%28%28x%2B3%29%29\"
\n" ); document.write( "cancel (x+3)
\n" ); document.write( "m = (x-5) is the slope \n" ); document.write( "
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