document.write( "Question 1106187: mrs.burgos wants to buy at least 30 kilos of pork and beef but can spend no more than 1200. A kilo of pork is 180 and 220 for beef.\r
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Algebra.Com's Answer #721137 by ikleyn(52884)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let X = kilos of pork, Y = kilos of beef.\r\n" );
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document.write( "Inequalities  (= mathematical model)\r\n" );
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document.write( "    x + Y >= 30,\r\n" );
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document.write( "    180X + 220Y <= 1200\r\n" );
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document.write( "    x >= 0,  Y >= y.\r\n" );
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document.write( "The plots are below:\r\n" );
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document.write( "Plots  X + Y = 30 (red),  180X + 220Y = 1200 (green).\r\n" );
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document.write( "The solution domain is the area in QI over the red line and below green line.\r\n" );
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document.write( "It is the EMPTY set (empty intersection). Which means that the problem  HAS NO  solutions.\r\n" );
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document.write( "The set of solutions to the given problem is  EMPTY.\r\n" );
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