document.write( "Question 1106190: Hi
\n" ); document.write( "andrew and carol had 160 dollars altogether. Andrew gave 1/3 of his money to carol. Then carol gave 1/5 of the amount she had back to andrew. Finally both had 80 dollars each. How much did andrew have at first. \r
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Algebra.Com's Answer #721133 by ikleyn(52787)\"\" \"About 
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\n" ); document.write( "Andrew and Carol had 160 dollars altogether. Andrew gave 1/3 of his money to Carol. Then carol gave 1/5 of the amount
\n" ); document.write( "she had back to Andrew. Finally both had 80 dollars each. How much did Andrew have at first.
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document.write( "1.  Let x = \"How much did andrew have at first\".\r\n" );
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document.write( "    Then Carol had (160-x) dollars.\r\n" );
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document.write( "2.  When Andrew gave 1/3 of his money to Carol, Carol had  \"160-x+%2B%281%2F3%29x\" = \"160-%282%2F3%29X\" dollars.\r\n" );
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document.write( "3.  Then Carol gave 1/5 of the amount she had back to Andrew. After that Carol had  \"%284%2F5%29%2A%28160-2%2F3%29x\" dollars.\r\n" );
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document.write( "    And the condition says that this amount is exactly 80 dollars:\r\n" );
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document.write( "    \"%284%2F5%29%2A%28160-2%2F3%29x\" = 80.\r\n" );
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document.write( "    It is your equation to find \"x\".  First, multiply both sides by \"5%2F4\". You will get\r\n" );
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document.write( "    160 - (2/3)x}}} = \"80%2A%285%2F4%29\" = 100.  ====>\r\n" );
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document.write( "    \"%282%2F3%29x\" = 160 - 100 = 60  ====>  x = \"60%2A%283%2F2%29\" = 90.\r\n" );
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document.write( "Answer.  Andrew had 90 dollars at first.   // which means that Carol had 160-90 = 70 dollars at first.\r\n" );
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document.write( "Check.   After n.2 exchange  Andrew had 90-30 = 60;  Carol had  70+30 = 100 dollars.\r\n" );
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document.write( "         After n.3 exchange Andrew had 60+20 = 80;  Carol had  100-20 = 80.\r\n" );
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document.write( "         80 = 80.    ! Correct !\r\n" );
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