document.write( "Question 1106166: In 2011, Julie will be the same age as the square of her age in 2005. How old is Julie in 2008? \n" ); document.write( "
Algebra.Com's Answer #721101 by josgarithmetic(39620)\"\" \"About 
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time 0, year 2005
\n" ); document.write( "time 3, year 2008
\n" ); document.write( "time 6, year 2011\r
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\n" ); document.write( "\n" ); document.write( "j, Julie's age at time 0.
\n" ); document.write( "At time 6, Julie will be j^2.
\n" ); document.write( "\"j%2B6=j%5E2\"\r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"j%5E2-j-6=0\"
\n" ); document.write( "\"%28j%2B2%29%28j-3%29=0\"
\n" ); document.write( "\"j=3\"----------Julie's age at time 0, year 2005.\r
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\n" ); document.write( "\n" ); document.write( "Julie in 2008, 3 years greater than j;
\n" ); document.write( "\"3%2B3=highlight%286%29\"
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