document.write( "Question 1106122: Hi
\n" ); document.write( "find the inverse function for the following\r
\n" ); document.write( "\n" ); document.write( "f(x) = x^2+2x where x is greater than or equal to 0\r
\n" ); document.write( "\n" ); document.write( "thanks
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Algebra.Com's Answer #721063 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!
looking for g(x) such that g(f(x)) = x (i.e. if g(x) is the inverse function of f(x) then when it is applied to f(x) it should give us back x.\r
\n" ); document.write( "\n" ); document.write( "\"+f%28x%29+=+x%5E2+%2B+2x+\"
\n" ); document.write( "\"+f%28x%29+%2B+1+=+x%5E2+%2B+2x+%2B+1+\"
\n" ); document.write( "\"+sqrt%28f%28x%29+%2B+1%29+=+x%2B1+\"
\n" ); document.write( "\"+sqrt%28f%28x%29%2B1%29+-+1+=+x+\"\r
\n" ); document.write( "\n" ); document.write( "The LHS is the g(x) we were seeking, just replace \"f(x)\" with \"x\", and note that the domain for this x is \"x%3E=0\" because f(x) >= 0 for x>=0:
\n" ); document.write( " \"++highlight%28g%28x%29+=+-1+%2B+sqrt%28x%2B1%29%29\" \"+x%3E=0\"\r
\n" ); document.write( "\n" ); document.write( "—
\n" ); document.write( "Check: g(f(x)) = \"+-1+%2B+sqrt%28%28x%5E2%2B2x%29%2B1%29+=+-1+%2B+%28x%2B1%29+=+x+\" (ok)
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