document.write( "Question 1106104: A car radiator needs a 70% antifreeze solution. The radiator now holds 20 liters of a 60% solution. How many liters of this should be drained and replaced with 100% antifreeze to get the desired strength? \n" ); document.write( "

Algebra.Com's Answer #721047 by ikleyn(52777) $\"\"$ $\"About$

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\n" ); document.write( "A car radiator needs a 70% antifreeze solution. The radiator now holds 20 liters of a 60% solution.
\n" ); document.write( "How many liters of this should be drained and replaced with 100% antifreeze to get the desired strength?
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document.write( "Let V be the volume to drain off from 20 liters of antifreeze.\r\n" );
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document.write( "Step 1:  Draining.  After draining,  you have 20-V liters of the 60% antifreeze.\r\n" );
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document.write( "                    It contains 0.60*(20-V) of pure antifreeze.\r\n" );
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document.write( "Step 2:  Replacing.  Then you add V liters of the pure antifreeze (the replacing step).\r\n" );
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document.write( "                     After the replacing,  you have the same total liquid volume of 20 liters.\r\n" );
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document.write( "                     It contains 0.60*(20-V) + V liters of pure antifreeze.\r\n" );
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document.write( "So, the antifreeze concentration after replacement is  . \r\n" );
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document.write( "It is the ratio of the pure antifreeze volume to the total volume.\r\n" );
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document.write( "Therefore, the concentration equation is \r\n" );
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document.write( " = 0.70.    (1)   \r\n" );
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document.write( "The setup is done and completed.\r\n" );
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document.write( "To solve the equation (1), multiply both sides by 20. You will get\r\n" );
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document.write( "0.6*(20-V) + V = 0.7*20,\r\n" );
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document.write( "12 - 0.6V + V = 14,\r\n" );
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document.write( "0.4V = 14 - 12 = 2  ====>  V =  = 5 liters.\r\n" );
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document.write( "Answer.  5 liters of the 60% antifreeze must be drained and replaced by 5 liters of pure antifreeze.\r\n" );
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document.write( "Check.    = 0.7.   ! Correct !\r\n" );
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\n" ); document.write( "There is entire bunch of introductory lessons covering various types of mixture problems\r
\n" ); document.write( "\n" ); document.write( "    - Mixture problems\r
\n" ); document.write( "\n" ); document.write( "    - More Mixture problems\r
\n" ); document.write( "\n" ); document.write( "    - Solving typical word problems on mixtures for solutions \r
\n" ); document.write( "\n" ); document.write( "    - Word problems on mixtures for antifreeze solutions (*)\r
\n" ); document.write( "\n" ); document.write( "    - Word problems on mixtures for alloys \r
\n" ); document.write( "\n" ); document.write( "    - Typical word problems on mixtures from the archive\r
\n" ); document.write( "\n" ); document.write( "in this site.\r
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\n" ); document.write( "\n" ); document.write( "Read them and become an expert in solution mixture word problems.
\n" ); document.write( "Notice that among these lessons there is one on antifreeze solutions marked by (*).\r
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\n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this textbook in the section \"Word problems\" under the topic \"Mixture problems\".\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Save the link to this online textbook together with its description\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-I
\n" ); document.write( "https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson\r
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\n" ); document.write( "\n" ); document.write( "to your archive and use it when it is needed.\r
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