document.write( "Question 1106060: The graph of the conic equation has vertices and foci equal to ?? \n" );
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Algebra.Com's Answer #721043 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The equation has both x^2 and y^2 terms, with the same sign and different coefficients, so the equation is of an ellipse. \n" ); document.write( "The standard form of the equation of an ellipse is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "In both formulas, (h,k) is the center of the ellipse; and a and b are the semi-major and semi-minor axes, respectively. \n" ); document.write( "Two different forms of the equation are necessary, because for the ellipse the a has to be the length of the semi-major axis. \n" ); document.write( "Parameter c is the distance from the center of the ellipse to each focus; for an ellipse, \n" ); document.write( "To find the vertices and foci, you need to put the given equation in the standard form. To do that, you need to complete the square in both x and y, then divide by the appropriate constant to get the right side of the equation equal to 1. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This is in standard form: \n" ); document.write( "The center of the ellipse is (h,k) = (-6,0). \n" ); document.write( "a is 7; the semi-major axis has length 7 in the x direction, so the vertices are at (-13,0) and (1,0). \n" ); document.write( "b is 4; the semi-major axis has length 4 in the y direction. If you need the co-vertices, they are 4 units in the positive and negative y direction from the center -- at (-6,-4) and (-6,4). \n" ); document.write( "The distance from the center to each focus is c, which is \n" ); document.write( " \n" ); document.write( " |