document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1106105>Question 1106105</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In an isosceles trapezoid ABCD, the smaller base is AB, AE and BF are altitudes drawn to side DC. If AE=7ft and DE=8ft, find angle D to the nearest degree. Then find AD using trigonometric ratios. Round AD to the nearest unit. \r<BR>\n" );
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document.write( "I got that angle D equals 41 degrees, but I am not sure how to find AD using trigonometric ratios????? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #721036 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=721036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I agree that to the nearest degree <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=D=41%5Eo ALIGN=MIDDLE  ALT=\"D=41%5Eo\"   DISABLED_style= \"max-width:90%; height:auto;\" > .<BR>\n" );
document.write( "From there, you could use the trigonometric ratios <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%28D%29=AE%2FAD ALIGN=MIDDLE  ALT=\"sin%28D%29=AE%2FAD\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%28D%29=DE%2FAD ALIGN=MIDDLE  ALT=\"cos%28D%29=DE%2FAD\"   DISABLED_style= \"max-width:90%; height:auto;\" > .<BR>\n" );
document.write( "You could say that<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%28D%29=AE%2FAD ALIGN=MIDDLE  ALT=\"sin%28D%29=AE%2FAD\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%2841%5Eo%29=7ft%2FAD ALIGN=MIDDLE  ALT=\"sin%2841%5Eo%29=7ft%2FAD\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and using the approximate value  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%2841%5Eo%29=0.656 ALIGN=MIDDLE  ALT=\"sin%2841%5Eo%29=0.656\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.656=7ft%2FAD ALIGN=MIDDLE  ALT=\"0.656=7ft%2FAD\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.656AD=7ft ALIGN=MIDDLE  ALT=\"0.656AD=7ft\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=AD=7ft%2F0.656 ALIGN=MIDDLE  ALT=\"AD=7ft%2F0.656\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=AD=10.67ft ALIGN=MIDDLE  ALT=\"AD=10.67ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >(rounded)<BR>\n" );
document.write( "To the nearest unit <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=AD=highlight%2811ft%29 ALIGN=MIDDLE  ALT=\"AD=highlight%2811ft%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > .<BR>\n" );
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document.write( "The problem makes sense if you are only able to use trigonometric value tables,<BR>\n" );
document.write( "just like I did before Hewlett Packard started selling calculators.<BR>\n" );
document.write( "With a calculator, you could give your answers with more decimal places,<BR>\n" );
document.write( "and you may even be tempted to calculate AD using the Pythagorean theorem, as<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=AD=sqrt%28AE%5E2%2BDE%5E2%29=sqrt%28%287ft%29%5E2%2B%288ft%29%5E2%29=sqrt%2849ft%5E2%2B64ft%5E2%29=sqrt%28113ft%5E2%29=10.63ft ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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