document.write( "Question 1106095: A two digit number whose ten digit is 2 more than the units digit is 3 more than 6 times the sum of its digits. Find the original number \n" ); document.write( "
Algebra.Com's Answer #721014 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "(1) Let the units digit be x; then the tens digit is x+2.

\n" ); document.write( "(2) The value of the number is 10(x+2)+x = 11x+20.

\n" ); document.write( "(3) 3 more than 6 times the sum of the digits is 6((x+2)+x)+3 = 12x+15.

\n" ); document.write( "The problem tells us that the expressions in (2) and (3) are equal:
\n" ); document.write( "\"11x%2B20+=+12x%2B15\"
\n" ); document.write( "\"5+=+x\"

\n" ); document.write( "The units digit is 5; the tens digit is 7.

\n" ); document.write( "CHECK: 6(5+7)+3 = 75
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