document.write( "Question 1105746: The police notice 5 drunken drivers daily in average with the variance 4, independently everyday. What is the probability that they catch over 1900 drunken drivers yearly?
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Algebra.Com's Answer #720982 by rothauserc(4718)\"\" \"About 
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1900/365 = 5.2 daily
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\n" ); document.write( "assume a normal distribution
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\n" ); document.write( "z-score = (5.2 - 5) / 4 = 0.05
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\n" ); document.write( "checking table of z-scores, we find
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\n" ); document.write( "Probability (P) ( X < 5.2 ) = 0.5199
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\n" ); document.write( "P ( X > 5.2 ) = 1 - 0.5199 = 0.4801 approximately 0.48
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