document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1106035>Question 1106035</A>: <I><SPAN STYLE=\"word-break: break-all;\">  solve for the ratio u:v if uČ+3uv-10vČ=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #720954 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=720954\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> factor the equation to get:\r<BR>\n" );
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document.write( "(u - 2v) * (u + 5v) = 0\r<BR>\n" );
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document.write( "solve for u to get:\r<BR>\n" );
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document.write( "u = 2v or u = -5v\r<BR>\n" );
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document.write( "divide both sides of these equations by v to get:\r<BR>\n" );
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document.write( "u/v = 2 or u/v = -5\r<BR>\n" );
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document.write( "i've never done one like this before, but i think that might be your answer.\r<BR>\n" );
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document.write( "i did some checking on the original equation and found that the equation is true when you assume these ratios.\r<BR>\n" );
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document.write( "from u/v = 2, i re-derived u = 2v.<BR>\n" );
document.write( "i then let v = 2 and u = 4 and the original equation became true with those values for u and v.\r<BR>\n" );
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document.write( "from u/v= -5, i let v = 10 and u = -50 and the original equation became true with those values for u and v.\r<BR>\n" );
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document.write( "consequently, i believe your solution is that u/v = 2 or u/v = -5.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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